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7.66. In an isosceles trapezoid which has base angles measuring 60 , find the lengths of (a) the lower base and altitude if the upper base has length 12 and the legs have length 16; (b) the upper base and altitude if the lower base has length 45 and the legs have length 28. (7.39) 7.67. In an isosceles right triangle, find the length of each leg if the hypotenuse has length (a) 34; (b) 2a. Find the length of the hypotenuse if each leg has length (c) 34; (d) 15 22. (7.40) 7.68. In a square, find the length of (a) the side if the diagonal has length 40; (b) the diagonal if the side has length 40. (7.40) 7.69. In an isosceles trapezoid which has base angles of measure 45 , find the lengths of (a) the lower base and each leg if the altitude has length 13 and the upper base has length 19; (b) the upper base and each leg if the altitude has length 27 and the lower base has length 65; (c) each leg and the lower base if the upper base has length 25 and the altitude has length 15. (7.40) 7.70. A parallelogram has an angle measuring 45 . Find the distances between its pairs of opposite sides if its sides have lengths 10 and 12. (7.40)

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+ 9,

(c) Up 3 spaces and 7 spaces to the left (d) Down 2 spaces and 8 spaces to the right (e) Up 4 spaces and to the left 1 space

CHAP. I]

18.5. Let trapezoid ABCD be formed by A(1, 3), B(5, 3), C(4, 1), and D(2, 1). Graph trapezoid ABCD and its image under (a) reflection across the y axis P(x, y) A P ( x, y) , (b) reflection across the line y 1, P(x, y) A Ps(x, 2 y), and (c) reflection across the line x 8, P(x, y) A P-(16 x, y). 18.6. Name the reflection that takes ^ABC to (a) ^ArBrCr, (b) ^AsBsCs, and (c) ^A-B-C- as illustrated in Fig. 18-18.

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(x 3 + 4)Dx (x 2 + x 2) (x 2 + x 2)Dx (x 3 + 4) (x 3 + 4)2 (x 3 + 4)(2x + 1) (x 2 + x 2)(3x 2 ) (x 3 + 4)2 (2x 4 + x 3 + 8x + 4) (3x 4 + 3x 3 6x 2 ) (x 3 + 4)2 x 4 2x 3 + 6x 2 + 8x + 4 (x 3 + 4)2

Because we are assuming zero initial conditions, y(- 1) = 0, and because the input consists of a linear combination of a scaled unit sample and a scaled delayed step, the solution to the difference equation is simply

Fig. 18-18

where h(n) and s(n) are the unit sample and unit step response, respectively. To find the unit sample response, we write the difference equation in the form

and the homogeneous solution is y(n)=Avn n>O Because the input x(n) = S(n) is equal to zero for n > 0, the particular solution is zero (all that the unit sample does is set the initial condition at n = 0). Evaluating the difference equation at n = 0, we have

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18.7. Name the transformation that (a) Reflects across y (b) Reflects across x (c) Reflects across y (d) Reflects across x 5 2 1

The step response may now be found by convolving h(n) with u(n):

Fig. 18-19

13.5 Find the slope-intercept equation of the tangent line to the graph of y = 1/x 3 when x = 1 . 2

We now want to find the value of d so thal after 360 equal monthly payments the mortgage is paid off. In other words. we want to find d such that

18.9. Let parallelogram ABCD be defined by A(1, 2), B(4, 2), C(5, 1), and D(2, 1). Graph parallelogram ABCD and its image under (a) a 90 clockwise rotation about the origin, (b) a 180 rotation about the origin, and (c) a 270 clockwise rotation about the origin.

With v = % and p = 100,000, we have d = 877.57 The total payment to the bank after 30 years is C = (877.57)(360) = 315,925.20

Name the rotation that takes ^ABC to (a) ^ArBrCr, (b) ^AsBsCs , and (c) ^A-B-C- as illustrated in Fig. 18-20.

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